** Operator precedence and the order of evaluation** plays a major role when two or more operators are used in a statement.

**For example:** a = b + c * d – e / z;

After executing the above statement, which operator will be evaluated first? Whether`(a = b) or (b + c) or (c * d ) or (d - e)`

and so on… The solution to this answer can be given by the below operator precedence table.

We can also remember the priorities of a few operators with **BODMAS** rules. i.e.

– Brackets**B**– Order of (or) Power of**O**– Division**D**– Multiplication**M**– Addition**A**– Subtraction**S**

### Exercise #1:

`a = b + c * d - e / z`

Let’s solve this expression by using the above-given table or the BODMAS rule. The division has higher priority than multiplication and the priority goes with addition, subtraction, and assignment.

- temp1 = e / z
- temp2 = c * d
- temp3 = b + temp2
- temp4 = temp3 – temp1
- a = temp4

Note: In the above expression all the operators, except assignment have the left to right evaluation order that is the reason, why e is divided by z. In the case of the assignment operator, the right-side value is assigned to the left due to the right to left order.

As a good programming practise, we can also change the expression like a = (((b+c) * (d-e)) / z) . Brackets remove the ambiguity and also improve the code readability.